waves & particles
progress ~25%
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updated 2025-11-19
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certainty likely
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importance high
This goal of this expository is to awaken the curiosity of the reader. It is based on notes from lectures & textbooks and may contain errors. Familiarity with mathematical tools is assumed.
1. Photons
Planck hypothesized in 1900 that, for an electromagnetic wave with frequency $\nu$, the only possible energies are of the form $nh\nu$, where $n$ is an integer and $h$ is a new constant. Einstein generalized it in 1905 and proposed that, light is made up of a beam of photons, each with energy $h\nu$. This allowed Einstein to explain the photoelectric effect. The photon was shown to exist 18 years later in 1923, by the Compton effect. Particle parameters and wave parameters can be related by: \[ \boxed{E = h\nu = \hbar \omega} \tag{1} \] where $\hbar = h / 2\pi$ and $h \approx 6.62 \times 10^{-34}$ Joule $\times$ second. And \[ \boxed{\mathbf{p} = \hbar \mathbf{k}} \tag{2} \] where $\mathbf k$ is the wave vector. These are the Planck-Einstein relations.
Thus, we have adopted a particle theory of light. But this purely particle framework is not able to explain typical wave phenomena such as interference and diffraction. Young's well-known double-slit experiment leads us to reject both the purely corpuscular and the purely wave interpretations. The concept of wave-particle duality states that, the particle and wave aspects of light are inseparable. Light behaves both like a wave and a flux of particles. The information about a photon at time $t$ is given by the wave $E(\mathbf r, t)$, which is a solution of Maxwell's equations. The probability amplitude of a photon appearing, at time $t$, at the point $\mathbf r$ is given by $E(\mathbf r, t)$.
2. Matter waves
The study of atomic emission and absorption spectra uncovered a fact, an atom emits or absorbs only photons having well-determined frequencies. The emission or absorption of a photon results in a jump in the energy of the atom from one permitted value to another. This implies that the energy of the atom can take on only certain discrete values and is hence, quantized.
To explain these quantization rules, de Broglie hypothesised in 1923 that, similar to photons, material particles can have a wavelike aspect as well. Electron diffraction experiments later confirmed this by showing that interference patterns could be obtained with material particles such as electrons. We therefore associate with a material particle, a wave whose parameters $\omega$ and $\mathbf k$ are given by the same relations as for photons. The wavelength of a matter wave is: \[ \lambda = \frac{2\pi}{|\mathbf k|} = \frac{h}{|\mathbf p|} \tag{3} \]
Similar to photons, the quantum state of a particle is characterized by a wave function $\psi(\mathbf r, t)$, which contains all the information it is possible to obtain about the particle. The probability of the particle being, at time $t$, in a volume element $\mathrm d^3 r$ situated at the point $\mathbf r$ is: \[ dP(\mathbf r, t) = C \; |\psi(\mathbf r, t)|^2 \; \mathrm d^3 r \tag{4} \] Hence, $|\psi(\mathbf r, t)|^2$ is the probability density, where $C$ is a normalization constant. Since the probability of finding the particle anywhere in space is $1$: \[ \frac{1}{C} = \int |\psi(\mathbf r, t)|^2 \; \mathrm d^3 r \tag{5} \] Schrödinger equation, postulated by Erwin Schrödinger in 1925, describes the evolution of $\psi(\mathbf r, t)$. When a particle of mass $m$ is subjected to a potential $V(\mathbf r, t)$, the Schrödinger equation takes on the form: \[ \boxed{i\hbar \frac{\partial}{\partial t} \psi(\mathbf r, t) = - \frac{\hbar^2}{2m}\Delta\psi(\mathbf r, t) + V(\mathbf r, t)\psi(\mathbf r, t)} \tag{6} \] The Schrödinger equation is analogous to Newton's second law in classical mechanics.
3. Free particle
We begin with the simplest case of all: the free particle. When $V(\mathbf r, t) = 0$ everywhere, the Schrödinger equation becomes: \[ i\hbar \frac{\partial}{\partial t} \psi(\mathbf r, t) = - \frac{\hbar^2}{2m}\Delta\psi(\mathbf r, t) \tag{7} \] This differential equation is satisfied by solutions of the form: \[ \psi(\mathbf r, t) = A e^{i(\mathbf k \cdot \mathbf r - \omega t)} \tag{8} \] where $A$ is a constant and \[ \omega = \frac{\hbar \mathbf k^2}{2m} \tag{9} \] This wave represents a particle whose probability of presence is uniform everywhere, since \[ |\psi(\mathbf r, t)|^2 = |A|^2 \tag{10} \] We also see that, (9) implies that energy $E$ and momentum $\mathbf p$ of a free particle satisfy: \[ E = \frac{\mathbf p^2}{2m} \tag{11} \] which is well-known in classical mechanics.
4. Wave packet
We begin by noticing that (6) is linear and homogeneous in $\psi$. According to the principle of superposition, every linear combination of plane waves satisfying (9) will also be a solution of equation (7). Such a superposition can be written as: \[ \psi(\mathbf r, t) = \frac{1}{(2\pi)^{3/2}} \int g(\mathbf k) e^{i[\mathbf k \cdot \mathbf r-\omega(k)t]} \; \mathrm d^3k \tag{12} \] A wave function like this is called a three-dimensional wave packet. A plane wave of form (8), whose modulus is constant throughout all space, is not square-integrable, and hence, not normalizable. Therefore, it cannot represent a physically-realizable state. On the other hand, a superposition of plane waves like $(12)$ can be square-integrable. For simplicity, we will study the one-dimensional case: \[ \psi(x, t) = \frac{1}{(2\pi)^{1/2}} \int_{-\infty}^{\infty} g(k) e^{i[k x-\omega(k)t]} \; \mathrm dk \tag{13} \] If we choose $t = 0$, the wave function becomes: \[ \psi(x, 0) = \frac{1}{(2\pi)^{1/2}} \int_{-\infty}^{\infty} g(k) e^{ikx} \; \mathrm dk \tag{14} \] Hence, $g(k)$ is simply the Fourier transform of $\psi(x, 0)$: \[ g(k) = \frac{1}{(2\pi)^{1/2}} \int_{-\infty}^{\infty} \psi(x, 0) e^{-ikx} \; \mathrm dx \tag{15} \]
5. Stationary states
The wave function of a particle when $V(\mathbf r)$ is time-independent must satisfy: \[ i\hbar \frac{\partial}{\partial t} \psi(\mathbf r, t) = - \frac{\hbar^2}{2m}\Delta\psi(\mathbf r, t) + V(\mathbf r)\psi(\mathbf r, t) \tag{16} \] In this case, the Schrödinger equation can be solved by separation of variables. We will look for solutions of the form: \begin{align} \psi(\mathbf r, t) & = \varphi(\mathbf r) \phi(t) \tag{17} \\ \\ \implies i\hbar \, \varphi(\mathbf r) \frac{\mathrm d \phi(t)}{\mathrm d t} & = - \frac{\hbar^2}{2m}\Delta\varphi(\mathbf r) \phi(t) + V(\mathbf r)\varphi(\mathbf r) \phi(t) \tag{18} \\ \\ \implies \frac{i\hbar}{\phi(t)} \frac{\mathrm d \phi(t)}{\mathrm d t} & = - \frac{1}{\varphi(\mathbf r)}\frac{\hbar^2}{2m}\Delta\varphi(\mathbf r) + V(\mathbf r) \tag{19} \\ \end{align} This equation equates a function of $t$ only with a function of $\mathbf r$ only. Hence, each of these functions is a constant, which we will set equal to $\hbar \omega$. The left-hand side gives us: \[ \phi(t) = Ae^{-i\omega t} \tag{20} \] And, the right-hand side: \[ \left[- \frac{\hbar^2}{2m}\Delta + V(\mathbf r)\right]\varphi(\mathbf r) = \hbar \omega \, \varphi(\mathbf r) \tag{21} \] We will absorb $A$ in $\varphi(\mathbf r)$: \[ \psi(\mathbf r, t) = \varphi(\mathbf r)e^{-i\omega t} \tag{22} \] This is called a stationary solution of the Schrödinger equation. A stationary state is a state with a well-defined energy $E = \hbar\omega$. Hence, we can re-write $(21)$ as: \[ \boxed{H \, \varphi(\mathbf r) = E \, \varphi(\mathbf r)} \tag{23} \] where $H$ is the differential operator: \[ H = - \frac{\hbar^2}{2m}\Delta + V(\mathbf r) \tag{24} \] $H$ is a linear operator and $(23)$ is the eigenvalue equation of $H$. The allowed energies are the eigenvalues of $H$. Equation $(23)$ is called the time-independent Schrödinger equation. It enables us to find, amongst all the possible states of the particle, those which are stationary. We will label the various possible values of the energy $E$ and the corresponding eigenfunctions $\varphi(\mathbf r)$ with index $n$. Thus: \[ H \, \varphi_n(\mathbf r) = E_n \, \varphi_n(\mathbf r) \tag{25} \] And, wave functions of the stationary states of the particle: \[ \psi_n(\mathbf r, t) = \varphi_n(\mathbf r)e^{-iE_nt/\hbar} \tag{26} \] The (time-dependent) Schrödinger equation $(6)$ has a property that every linear combination of solutions is itself a solution: \[ \psi(\mathbf r, t) = \sum_n c_n\varphi_n(\mathbf r)e^{-iE_nt/\hbar} \tag{27} \] where the coefficients $c_n$ are complex constants. In particular, we have: \[ \psi(\mathbf r, 0) = \sum_n c_n\varphi_n(\mathbf r) \tag{28} \] If we know $\psi(\mathbf r, 0)$, the state of the particle at $t = 0$. We can always decompose it in terms of eigenfunctions of $H$. The corresponding solution $\psi(\mathbf r, t)$ of the Schrödinger equation is then given by $(27)$, by simply multiplying each term of $(28)$ by $e^{-iE_nt/\hbar}$ where $E_n$ is the eigenvalue associated with $\varphi_n(\mathbf r)$.
6. Square potential
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